2/5(b-10)=26

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Solution for 2/5(b-10)=26 equation:



2/5(b-10)=26
We move all terms to the left:
2/5(b-10)-(26)=0
Domain of the equation: 5(b-10)!=0
b∈R
We multiply all the terms by the denominator
-26*5(b-10)+2=0
Wy multiply elements
-130b(b+2=0

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