2/5(b-10)=26

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Solution for 2/5(b-10)=26 equation: 



2/5(b-10)=26

We move all terms to the left:

2/5(b-10)-(26)=0



Domain of the equation: 5(b-10)!=0

b∈R



We multiply all the terms by the denominator


-26*5(b-10)+2=0

Wy multiply elements

-130b(b+2=0

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