2/5(b-5)=8/5b

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Solution for 2/5(b-5)=8/5b equation: 



2/5(b-5)=8/5b

We move all terms to the left:

2/5(b-5)-(8/5b)=0



Domain of the equation: 5(b-5)!=0

b∈R





Domain of the equation: 5b)!=0

b!=0/1

b!=0

b∈R



We add all the numbers together, and all the variables

2/5(b-5)-(+8/5b)=0

We get rid of parentheses

2/5(b-5)-8/5b=0

We calculate fractions


10b/(25b^2-125b)+(-40bb/(25b^2-125b)=0



We calculate terms in parentheses: +(-40bb/(25b^2-125b), so:

-40bb/(25b^2-125b

We multiply all the terms by the denominator


-40bb

Back to the equation:

+(-40bb)



We get rid of parentheses

10b/(25b^2-125b)-40bb=0

We multiply all the terms by the denominator


10b-40bb*(25b^2-125b)=0

We multiply parentheses

-1000b^3+5000b^2+10b=0

We do not support ebpression: b^3

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