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2/5(h+5)=h+6
We move all terms to the left:
2/5(h+5)-(h+6)=0
Domain of the equation: 5(h+5)!=0We get rid of parentheses
h∈R
2/5(h+5)-h-6=0
We multiply all the terms by the denominator
-h*5(h+5)-6*5(h+5)+2=0
Wy multiply elements
-5h^2(h-30h(h+2=0
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