2/5(k+10)=2/k

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Solution for 2/5(k+10)=2/k equation: 



2/5(k+10)=2/k

We move all terms to the left:

2/5(k+10)-(2/k)=0



Domain of the equation: 5(k+10)!=0

k∈R





Domain of the equation: k)!=0

k!=0/1

k!=0

k∈R



We add all the numbers together, and all the variables

2/5(k+10)-(+2/k)=0

We get rid of parentheses

2/5(k+10)-2/k=0

We calculate fractions


2k/(5k^2+50k)+(-10kk/(5k^2+50k)=0



We calculate terms in parentheses: +(-10kk/(5k^2+50k), so:

-10kk/(5k^2+50k

We multiply all the terms by the denominator


-10kk

Back to the equation:

+(-10kk)



We get rid of parentheses

2k/(5k^2+50k)-10kk=0

We multiply all the terms by the denominator


2k-10kk*(5k^2+50k)=0

We multiply parentheses

-50k^3-500k^2+2k=0

We do not support ekpression: k^3

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