2/5(m)=-32

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Solution for 2/5(m)=-32 equation: 



2/5(m)=-32

We move all terms to the left:

2/5(m)-(-32)=0



Domain of the equation: 5m!=0

m!=0/5

m!=0

m∈R



We add all the numbers together, and all the variables

2/5m+32=0

We multiply all the terms by the denominator


32*5m+2=0

Wy multiply elements

160m+2=0

We move all terms containing m to the left, all other terms to the right

160m=-2

m=-2/160

m=-1/80

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