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2/5(m-5)+3/10(m+2)=24
We move all terms to the left:
2/5(m-5)+3/10(m+2)-(24)=0
Domain of the equation: 5(m-5)!=0
m∈R
Domain of the equation: 10(m+2)!=0We calculate fractions
m∈R
(20mm/(5(m-5)*10(m+2))+(15mm/(5(m-5)*10(m+2))-24=0
We can not solve this equation
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