2/5(n-10)+23=7/10n+1

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Solution for 2/5(n-10)+23=7/10n+1 equation: 



2/5(n-10)+23=7/10n+1

We move all terms to the left:

2/5(n-10)+23-(7/10n+1)=0



Domain of the equation: 5(n-10)!=0

n∈R





Domain of the equation: 10n+1)!=0

n∈R



We get rid of parentheses

2/5(n-10)-7/10n-1+23=0

We calculate fractions


20n/(50n^2-500n)+(-35nn/(50n^2-500n)-1+23=0

We calculate fractions

We do not support enpression: n^3

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