2/5(r-)=3/20(r-5)

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Solution for 2/5(r-)=3/20(r-5) equation: 



2/5(r-)=3/20(r-5)

We move all terms to the left:

2/5(r-)-(3/20(r-5))=0



Domain of the equation: 5(r-)!=0

r∈R





Domain of the equation: 20(r-5))!=0

r∈R



We add all the numbers together, and all the variables

2/5(+r)-(3/20(r-5))=0

We calculate fractions


(40rr/(5(+r)*20(r-5)))+(-15r0/(5(+r)*20(r-5)))=0



We calculate terms in parentheses: +(40rr/(5(+r)*20(r-5))), so:

40rr/(5(+r)*20(r-5))

We multiply all the terms by the denominator


40rr

Back to the equation:

+(40rr)





We calculate terms in parentheses: +(-15r0/(5(+r)*20(r-5))), so:

-15r0/(5(+r)*20(r-5))

We multiply all the terms by the denominator


-15r0

We add all the numbers together, and all the variables

-15r

Back to the equation:

+(-15r)



We get rid of parentheses

40rr-15r=0

We add all the numbers together, and all the variables

-15r+40rr=0

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