2/5(t+3.2)=28

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Solution for 2/5(t+3.2)=28 equation: 



2/5(t+3.2)=28

We move all terms to the left:

2/5(t+3.2)-(28)=0



Domain of the equation: 5(t+3.2)!=0

t∈R



We multiply all the terms by the denominator


-28*5(t+3.2)+2=0

Wy multiply elements

-140t(t+2=0

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