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2/5(x+2)=x-4
We move all terms to the left:
2/5(x+2)-(x-4)=0
Domain of the equation: 5(x+2)!=0We get rid of parentheses
x∈R
2/5(x+2)-x+4=0
We multiply all the terms by the denominator
-x*5(x+2)+4*5(x+2)+2=0
Wy multiply elements
-5x^2(x+20x(x+2=0
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