2/5(x+3)=3/2(x-1)=

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Solution for 2/5(x+3)=3/2(x-1)= equation: 



2/5(x+3)=3/2(x-1)=

We move all terms to the left:

2/5(x+3)-(3/2(x-1))=0



Domain of the equation: 5(x+3)!=0

x∈R





Domain of the equation: 2(x-1))!=0

x∈R



We calculate fractions


(4xx/(5(x+3)*2(x-1)))+(-15xx/(5(x+3)*2(x-1)))=0



We calculate terms in parentheses: +(4xx/(5(x+3)*2(x-1))), so:

4xx/(5(x+3)*2(x-1))

We multiply all the terms by the denominator


4xx

Back to the equation:

+(4xx)





We calculate terms in parentheses: +(-15xx/(5(x+3)*2(x-1))), so:

-15xx/(5(x+3)*2(x-1))

We multiply all the terms by the denominator


-15xx

Back to the equation:

+(-15xx)



We get rid of parentheses

4xx-15xx=0

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