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2/5(x-4)=1/2x
We move all terms to the left:
2/5(x-4)-(1/2x)=0
Domain of the equation: 5(x-4)!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2/5(x-4)-(+1/2x)=0
We get rid of parentheses
2/5(x-4)-1/2x=0
We calculate fractions
4x/(10x^2-40x)+(-5xx/(10x^2-40x)=0
We calculate terms in parentheses: +(-5xx/(10x^2-40x), so:We get rid of parentheses
-5xx/(10x^2-40x
We multiply all the terms by the denominator
-5xx
Back to the equation:
+(-5xx)
4x/(10x^2-40x)-5xx=0
We multiply all the terms by the denominator
4x-5xx*(10x^2-40x)=0
We multiply parentheses
-50x^3+200x^2+4x=0
We do not support expression: x^3
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