2/5(y-5)=1/5(y-10)+2

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Solution for 2/5(y-5)=1/5(y-10)+2 equation: 



2/5(y-5)=1/5(y-10)+2

We move all terms to the left:

2/5(y-5)-(1/5(y-10)+2)=0



Domain of the equation: 5(y-5)!=0

y∈R





Domain of the equation: 5(y-10)+2)!=0

y∈R



We calculate fractions


(10yy/(5(y-5)*5(y-10))+(-5yy/(5(y-5)*5(y-10))=0



We calculate terms in parentheses: +(10yy/(5(y-5)*5(y-10))+(-5yy/(5(y-5)*5(y-10)), so:

10yy/(5(y-5)*5(y-10))+(-5yy/(5(y-5)*5(y-10)

We calculate fractions


(10yy*(5(y-5)*5(y-10))/((5(y-5)*5(y-10))*(5(y-5)*5(y-10))+((-5yy*(5(y-5)*5(y-10)))/((5(y-5)*5(y-10))*(5(y-5)*5(y-10))



We calculate terms in parentheses: +(10yy*(5(y-5)*5(y-10))/((5(y-5)*5(y-10))*(5(y-5)*5(y-10))+((-5yy*(5(y-5)*5(y-10)))/((5(y-5)*5(y-10))*(5(y-5)*5(y-10)), so:

10yy*(5(y-5)*5(y-10))/((5(y-5)*5(y-10))*(5(y-5)*5(y-10))+((-5yy*(5(y-5)*5(y-10)))/((5(y-5)*5(y-10))*(5(y-5)*5(y-10)

We can not solve this equation

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