2/5*z-i=i/5*z-1

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Solution for 2/5*z-i=i/5*z-1 equation: 


x in (-oo:+oo)

(2/5)*z-i = (i/5)*z-1 // - (i/5)*z-1

(2/5)*z-i-((i/5)*z)+1 = 0

2/5*z-i-1/5*i*z+1 = 0

x należy do R

x in (-oo:+oo)

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