2/5+(4/(10x+5))=7/(2x+1)

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Solution for 2/5+(4/(10x+5))=7/(2x+1) equation:


D( x )

2*x+1 = 0

10*x+5 = 0

2*x+1 = 0

2*x+1 = 0

2*x+1 = 0 // - 1

2*x = -1 // : 2

x = -1/2

10*x+5 = 0

10*x+5 = 0

10*x+5 = 0 // - 5

10*x = -5 // : 10

x = -5/10

x = -1/2

x in (-oo:-1/2) U (-1/2:+oo)

4/(10*x+5)+2/5 = 7/(2*x+1) // - 7/(2*x+1)

4/(10*x+5)-(7/(2*x+1))+2/5 = 0

4/(10*x+5)-7*(2*x+1)^-1+2/5 = 0

4/(10*x+5)-7/(2*x+1)+2/5 = 0

(4*5*(2*x+1))/(5*(10*x+5)*(2*x+1))+(-7*5*(10*x+5))/(5*(10*x+5)*(2*x+1))+(2*(10*x+5)*(2*x+1))/(5*(10*x+5)*(2*x+1)) = 0

4*5*(2*x+1)-7*5*(10*x+5)+2*(10*x+5)*(2*x+1) = 0

40*x^2-310*x+40*x-155+10 = 0

40*x^2-270*x-145 = 0

40*x^2-270*x-145 = 0

5*(8*x^2-54*x-29) = 0

8*x^2-54*x-29 = 0

DELTA = (-54)^2-(-29*4*8)

DELTA = 3844

DELTA > 0

x = (3844^(1/2)+54)/(2*8) or x = (54-3844^(1/2))/(2*8)

x = 29/4 or x = -1/2

5*(x+1/2)*(x-29/4) = 0

(5*(x+1/2)*(x-29/4))/(5*(10*x+5)*(2*x+1)) = 0

(5*(x+1/2)*(x-29/4))/(5*(10*x+5)*(2*x+1)) = 0 // * 5*(10*x+5)*(2*x+1)

5*(x+1/2)*(x-29/4) = 0

( x+1/2 )

x+1/2 = 0 // - 1/2

x = -1/2

( x-29/4 )

x-29/4 = 0 // + 29/4

x = 29/4

x in { -1/2}

x = 29/4

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