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2/5+1/5h=33/5
We move all terms to the left:
2/5+1/5h-(33/5)=0
Domain of the equation: 5h!=0We add all the numbers together, and all the variables
h!=0/5
h!=0
h∈R
1/5h+2/5-(+33/5)=0
We get rid of parentheses
1/5h+2/5-33/5=0
We calculate fractions
=0
h=0/1
h=0
Równanie nie ma rozwiązania
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