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2/5-7=12/5x-2x+3
We move all terms to the left:
2/5-7-(12/5x-2x+3)=0
Domain of the equation: 5x-2x+3)!=0We add all the numbers together, and all the variables
x∈R
-(-2x+12/5x+3)-7+2/5=0
We get rid of parentheses
2x-12/5x-3-7+2/5=0
We calculate fractions
2x-3-7=0
We add all the numbers together, and all the variables
2x-10=0
We move all terms containing x to the left, all other terms to the right
2x=10
x=10/2
x=5
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