2/55h=4/5h+6

Solution for 2/55h=4/5h+6 equation:

2/55h=4/5h+6

We move all terms to the left:

2/55h-(4/5h+6)=0


Domain of the equation: 55h!=0

h!=0/55

h!=0

h∈R



Domain of the equation: 5h+6)!=0

h∈R


We get rid of parentheses

2/55h-4/5h-6=0

We calculate fractions


10h/275h^2+(-220h)/275h^2-6=0

We multiply all the terms by the denominator


10h+(-220h)-6*275h^2=0

Wy multiply elements

-1650h^2+10h+(-220h)=0

We get rid of parentheses

-1650h^2+10h-220h=0

We add all the numbers together, and all the variables

-1650h^2-210h=0

a = -1650; b = -210; c = 0;
Δ = b2-4ac
Δ = -2102-4·(-1650)·0
Δ = 44100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{44100}=210$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-210)-210}{2*-1650}=\frac{0}{-3300}
=0
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-210)+210}{2*-1650}=\frac{420}{-3300}
=-7/55
$