2/5=(x+3)/10

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Solution for 2/5=(x+3)/10 equation: 



2/5=(x+3)/10

We move all terms to the left:

2/5-((x+3)/10)=0

We calculate fractions


(-((x+3)*5)/()+()/()=0



We calculate terms in parentheses: +(-((x+3)*5)/()+()/(), so:

-((x+3)*5)/()+()/(

We add all the numbers together, and all the variables

-((x+3)*5)/()+1

We multiply all the terms by the denominator


-((x+3)*5)+1*()



We calculate terms in parentheses: -((x+3)*5), so:

(x+3)*5

We multiply parentheses

5x+15

Back to the equation:

-(5x+15)



We add all the numbers together, and all the variables

-(5x+15)

We get rid of parentheses

-5x-15

Back to the equation:

+(-5x-15)



We get rid of parentheses

-5x-15=0

We move all terms containing x to the left, all other terms to the right

-5x=15

x=15/-5

x=-3

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