2/5=1/3(2m-12)m=

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Solution for 2/5=1/3(2m-12)m= equation: 



2/5=1/3(2m-12)m=

We move all terms to the left:

2/5-(1/3(2m-12)m)=0



Domain of the equation: 3(2m-12)m)!=0

m∈R



We calculate fractions


()/(-150m)+(6m2/(-150m)=0



We calculate terms in parentheses: +(6m2/(-150m), so:

6m2/(-150m

We multiply all the terms by the denominator


6m2

We add all the numbers together, and all the variables

6m^2

Back to the equation:

+(6m^2)



determiningTheFunctionDomain
6m^2+()/(-150m)=0

We multiply all the terms by the denominator


6m^2*(-150m)+()=0

We add all the numbers together, and all the variables

6m^2*(-150m)=0

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