2/5=35/n

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Solution for 2/5=35/n equation:


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

2/5 = 35/n // - 35/n

2/5-(35/n) = 0

2/5-35*n^-1 = 0

-35*n^-1 = -2/5 // : -35

n^-1 = 2/175

-1 < 0

1/(n^1) = 2/175 // * n^1

1 = 2/175*n^1 // : 2/175

175/2 = n^1

n = 175/2

n = 175/2

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