2/5b+25=29

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Solution for 2/5b+25=29 equation: 



2/5b+25=29

We move all terms to the left:

2/5b+25-(29)=0



Domain of the equation: 5b!=0

b!=0/5

b!=0

b∈R



We add all the numbers together, and all the variables

2/5b-4=0

We multiply all the terms by the denominator


-4*5b+2=0

Wy multiply elements

-20b+2=0

We move all terms containing b to the left, all other terms to the right

-20b=-2

b=-2/-20

b=1/10

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