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2/5b+5=20-1b
We move all terms to the left:
2/5b+5-(20-1b)=0
Domain of the equation: 5b!=0We add all the numbers together, and all the variables
b!=0/5
b!=0
b∈R
2/5b-(-1b+20)+5=0
We get rid of parentheses
2/5b+1b-20+5=0
We multiply all the terms by the denominator
1b*5b-20*5b+5*5b+2=0
Wy multiply elements
5b^2-100b+25b+2=0
We add all the numbers together, and all the variables
5b^2-75b+2=0
a = 5; b = -75; c = +2;
Δ = b2-4ac
Δ = -752-4·5·2
Δ = 5585
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-75)-\sqrt{5585}}{2*5}=\frac{75-\sqrt{5585}}{10} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-75)+\sqrt{5585}}{2*5}=\frac{75+\sqrt{5585}}{10} $
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