2/5b+5=25

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Solution for 2/5b+5=25 equation: 



2/5b+5=25

We move all terms to the left:

2/5b+5-(25)=0



Domain of the equation: 5b!=0

b!=0/5

b!=0

b∈R



We add all the numbers together, and all the variables

2/5b-20=0

We multiply all the terms by the denominator


-20*5b+2=0

Wy multiply elements

-100b+2=0

We move all terms containing b to the left, all other terms to the right

-100b=-2

b=-2/-100

b=1/50

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