2/5c+17=19

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Solution for 2/5c+17=19 equation: 



2/5c+17=19

We move all terms to the left:

2/5c+17-(19)=0



Domain of the equation: 5c!=0

c!=0/5

c!=0

c∈R



We add all the numbers together, and all the variables

2/5c-2=0

We multiply all the terms by the denominator


-2*5c+2=0

Wy multiply elements

-10c+2=0

We move all terms containing c to the left, all other terms to the right

-10c=-2

c=-2/-10

c=1/5

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