2/5c+4-1/2c=-9

Solution for 2/5c+4-1/2c=-9 equation:

2/5c+4-1/2c=-9

We move all terms to the left:

2/5c+4-1/2c-(-9)=0


Domain of the equation: 5c!=0

c!=0/5

c!=0

c∈R



Domain of the equation: 2c!=0

c!=0/2

c!=0

c∈R


We add all the numbers together, and all the variables

2/5c-1/2c+13=0

We calculate fractions


4c/10c^2+(-5c)/10c^2+13=0

We multiply all the terms by the denominator


4c+(-5c)+13*10c^2=0

Wy multiply elements

130c^2+4c+(-5c)=0

We get rid of parentheses

130c^2+4c-5c=0

We add all the numbers together, and all the variables

130c^2-1c=0

a = 130; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·130·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*130}=\frac{0}{260}
=0
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*130}=\frac{2}{260}
=1/130
$