2/5c+4-1/5c=42

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Solution for 2/5c+4-1/5c=42 equation:



2/5c+4-1/5c=42
We move all terms to the left:
2/5c+4-1/5c-(42)=0
Domain of the equation: 5c!=0
c!=0/5
c!=0
c∈R
We add all the numbers together, and all the variables
2/5c-1/5c-38=0
We multiply all the terms by the denominator
-38*5c+2-1=0
We add all the numbers together, and all the variables
-38*5c+1=0
Wy multiply elements
-190c+1=0
We move all terms containing c to the left, all other terms to the right
-190c=-1
c=-1/-190
c=1/190

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