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2/5c-16=c
We move all terms to the left:
2/5c-16-(c)=0
Domain of the equation: 5c!=0We add all the numbers together, and all the variables
c!=0/5
c!=0
c∈R
-1c+2/5c-16=0
We multiply all the terms by the denominator
-1c*5c-16*5c+2=0
Wy multiply elements
-5c^2-80c+2=0
a = -5; b = -80; c = +2;
Δ = b2-4ac
Δ = -802-4·(-5)·2
Δ = 6440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6440}=\sqrt{4*1610}=\sqrt{4}*\sqrt{1610}=2\sqrt{1610}$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-2\sqrt{1610}}{2*-5}=\frac{80-2\sqrt{1610}}{-10} $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+2\sqrt{1610}}{2*-5}=\frac{80+2\sqrt{1610}}{-10} $
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