2/5c-5=17

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Solution for 2/5c-5=17 equation: 



2/5c-5=17

We move all terms to the left:

2/5c-5-(17)=0



Domain of the equation: 5c!=0

c!=0/5

c!=0

c∈R



We add all the numbers together, and all the variables

2/5c-22=0

We multiply all the terms by the denominator


-22*5c+2=0

Wy multiply elements

-110c+2=0

We move all terms containing c to the left, all other terms to the right

-110c=-2

c=-2/-110

c=1/55

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