2/5d-d=18

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Solution for 2/5d-d=18 equation:



2/5d-d=18
We move all terms to the left:
2/5d-d-(18)=0
Domain of the equation: 5d!=0
d!=0/5
d!=0
d∈R
We add all the numbers together, and all the variables
-1d+2/5d-18=0
We multiply all the terms by the denominator
-1d*5d-18*5d+2=0
Wy multiply elements
-5d^2-90d+2=0
a = -5; b = -90; c = +2;
Δ = b2-4ac
Δ = -902-4·(-5)·2
Δ = 8140
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{8140}=\sqrt{4*2035}=\sqrt{4}*\sqrt{2035}=2\sqrt{2035}$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-90)-2\sqrt{2035}}{2*-5}=\frac{90-2\sqrt{2035}}{-10} $
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-90)+2\sqrt{2035}}{2*-5}=\frac{90+2\sqrt{2035}}{-10} $

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