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2/5g-3=-1/2g
We move all terms to the left:
2/5g-3-(-1/2g)=0
Domain of the equation: 5g!=0
g!=0/5
g!=0
g∈R
Domain of the equation: 2g)!=0We get rid of parentheses
g!=0/1
g!=0
g∈R
2/5g+1/2g-3=0
We calculate fractions
4g/10g^2+5g/10g^2-3=0
We multiply all the terms by the denominator
4g+5g-3*10g^2=0
We add all the numbers together, and all the variables
9g-3*10g^2=0
Wy multiply elements
-30g^2+9g=0
a = -30; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·(-30)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*-30}=\frac{-18}{-60} =3/10 $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*-30}=\frac{0}{-60} =0 $
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