2/5h-7=12/2h-2h+3

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Solution for 2/5h-7=12/2h-2h+3 equation: 



2/5h-7=12/2h-2h+3

We move all terms to the left:

2/5h-7-(12/2h-2h+3)=0



Domain of the equation: 5h!=0

h!=0/5

h!=0

h∈R





Domain of the equation: 2h-2h+3)!=0

h∈R



We add all the numbers together, and all the variables

2/5h-(-2h+12/2h+3)-7=0

We get rid of parentheses

2/5h+2h-12/2h-3-7=0

We calculate fractions


2h+4h/10h^2+(-60h)/10h^2-3-7=0

We add all the numbers together, and all the variables

2h+4h/10h^2+(-60h)/10h^2-10=0

We multiply all the terms by the denominator


2h*10h^2+4h+(-60h)-10*10h^2=0

We add all the numbers together, and all the variables

4h+2h*10h^2+(-60h)-10*10h^2=0

Wy multiply elements

20h^3-100h^2+4h+(-60h)=0

We get rid of parentheses

20h^3-100h^2+4h-60h=0

We do not support ehpression: h^3

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