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h in (-oo:+oo)
(2/5)*h-7 = (12/5)*h-(2*h)+3 // - (12/5)*h-(2*h)+3
(2/5)*h-((12/5)*h)+2*h-7-3 = 0
(2/5)*h+(-12/5)*h+2*h-7-3 = 0
-10 = 0
h belongs to the empty set
h belongs to the empty set
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