If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2/5h-7=12/5h-2h+3+3
We move all terms to the left:
2/5h-7-(12/5h-2h+3+3)=0
Domain of the equation: 5h!=0
h!=0/5
h!=0
h∈R
Domain of the equation: 5h-2h+3+3)!=0We add all the numbers together, and all the variables
We move all terms containing h to the left, all other terms to the right
5h-2h+3)!=-3
h∈R
2/5h-(-2h+12/5h+6)-7=0
We get rid of parentheses
2/5h+2h-12/5h-6-7=0
We multiply all the terms by the denominator
2h*5h-6*5h-7*5h+2-12=0
We add all the numbers together, and all the variables
2h*5h-6*5h-7*5h-10=0
Wy multiply elements
10h^2-30h-35h-10=0
We add all the numbers together, and all the variables
10h^2-65h-10=0
a = 10; b = -65; c = -10;
Δ = b2-4ac
Δ = -652-4·10·(-10)
Δ = 4625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4625}=\sqrt{25*185}=\sqrt{25}*\sqrt{185}=5\sqrt{185}$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-65)-5\sqrt{185}}{2*10}=\frac{65-5\sqrt{185}}{20} $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-65)+5\sqrt{185}}{2*10}=\frac{65+5\sqrt{185}}{20} $
| 30+0.14x=0.18x | | 6z^2+25z+14=0 | | 8-5x=6x-113 | | -4(8+7x)=-10-^x | | 7n+5n=6 | | 2/5h-7=2.4h-2h+3 | | 0.3x-0.9x-17=1 | | 36=4w+6+2w | | 5(6x+12)+8=15(3x+8) | | 2x=x+38=2x+3 | | 8=8/9x | | x/6+7=22 | | 20-2y=-50 | | Y=c-18 | | 3/x=12/28 | | (3x+5)^(7/3)+22=150 | | 33=-u/5 | | 7d+2=2d+40 | | 8x+9=7-3x | | 5n-11=2n+1 | | 2(x-1)-3=125 | | y/4+15=38 | | -3/4=-2/3y-7/5 | | 2x-45=12+3x | | 5x+1+3x+13=180 | | 7.2x+5.7=6.3 | | 28=w/2-12 | | 7(x+5)=25 | | I3(y+5)=21 | | M=5x19 | | (z-10)=-6(2) | | -2(4w-1)+w=7(w+2) |