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2/5h-7=12/5h-3
We move all terms to the left:
2/5h-7-(12/5h-3)=0
Domain of the equation: 5h!=0
h!=0/5
h!=0
h∈R
Domain of the equation: 5h-3)!=0We get rid of parentheses
h∈R
2/5h-12/5h+3-7=0
We multiply all the terms by the denominator
3*5h-7*5h+2-12=0
We add all the numbers together, and all the variables
3*5h-7*5h-10=0
Wy multiply elements
15h-35h-10=0
We add all the numbers together, and all the variables
-20h-10=0
We move all terms containing h to the left, all other terms to the right
-20h=10
h=10/-20
h=-1/2
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