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2/5h=10/5h+11
We move all terms to the left:
2/5h-(10/5h+11)=0
Domain of the equation: 5h!=0
h!=0/5
h!=0
h∈R
Domain of the equation: 5h+11)!=0We get rid of parentheses
h∈R
2/5h-10/5h-11=0
We multiply all the terms by the denominator
-11*5h+2-10=0
We add all the numbers together, and all the variables
-11*5h-8=0
Wy multiply elements
-55h-8=0
We move all terms containing h to the left, all other terms to the right
-55h=8
h=8/-55
h=-8/55
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