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2/5h=2
We move all terms to the left:
2/5h-(2)=0
Domain of the equation: 5h!=0We multiply all the terms by the denominator
h!=0/5
h!=0
h∈R
-2*5h+2=0
Wy multiply elements
-10h+2=0
We move all terms containing h to the left, all other terms to the right
-10h=-2
h=-2/-10
h=1/5
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