2/5k-(k+1/2)=1/10(k+1)

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Solution for 2/5k-(k+1/2)=1/10(k+1) equation: 


k in (-oo:+oo)

(2/5)*k-k-(1/2) = (1/10)*(k+1) // - (1/10)*(k+1)

(2/5)*k-((1/10)*(k+1))-k-(1/2) = 0

(-1/10)*(k+1)+(2/5)*k-k-1/2 = 0

(2*k)/5-1/10*(k+1)-k-1/2 = 0

(-1/10*2*5*(k+1))/(2*5)+(2*2*k)/(2*5)+(2*5*(-k))/(2*5)+(-1*5)/(2*5) = 0

2*2*k-1/10*2*5*(k+1)+2*5*(-k)-1*5 = 0

3*k-10*k-5-1 = 0

-7*k-5-1 = 0

-7*k-6 = 0

(-7*k-6)/(2*5) = 0

(-7*k-6)/(2*5) = 0 // * 2*5

-7*k-6 = 0

-7*k-6 = 0 // + 6

-7*k = 6 // : -7

k = 6/(-7)

k = -6/7

k = -6/7

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