2/5k-(k+1/5)=1/25(k+5)

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Solution for 2/5k-(k+1/5)=1/25(k+5) equation: 



2/5k-(k+1/5)=1/25(k+5)

We move all terms to the left:

2/5k-(k+1/5)-(1/25(k+5))=0



Domain of the equation: 5k!=0

k!=0/5

k!=0

k∈R





Domain of the equation: 25(k+5))!=0

k∈R



We add all the numbers together, and all the variables

2/5k-(+k+1/5)-(1/25(k+5))=0

We get rid of parentheses

2/5k-k-(1/25(k+5))-1/5=0

We calculate fractions


-k+(50kk/(625k^2k+(-(1*5k*5)/(625k^2k+(-25kk/(625k^2k=0

We can not solve this equation

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