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2/5k=2
We move all terms to the left:
2/5k-(2)=0
Domain of the equation: 5k!=0We multiply all the terms by the denominator
k!=0/5
k!=0
k∈R
-2*5k+2=0
Wy multiply elements
-10k+2=0
We move all terms containing k to the left, all other terms to the right
-10k=-2
k=-2/-10
k=1/5
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