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2/5k=9
We move all terms to the left:
2/5k-(9)=0
Domain of the equation: 5k!=0We multiply all the terms by the denominator
k!=0/5
k!=0
k∈R
-9*5k+2=0
Wy multiply elements
-45k+2=0
We move all terms containing k to the left, all other terms to the right
-45k=-2
k=-2/-45
k=2/45
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