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2/5m+3=12
We move all terms to the left:
2/5m+3-(12)=0
Domain of the equation: 5m!=0We add all the numbers together, and all the variables
m!=0/5
m!=0
m∈R
2/5m-9=0
We multiply all the terms by the denominator
-9*5m+2=0
Wy multiply elements
-45m+2=0
We move all terms containing m to the left, all other terms to the right
-45m=-2
m=-2/-45
m=2/45
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