2/5m+8=m+1

Solution for 2/5m+8=m+1 equation:

2/5m+8=m+1

We move all terms to the left:

2/5m+8-(m+1)=0


Domain of the equation: 5m!=0

m!=0/5

m!=0

m∈R


We get rid of parentheses

2/5m-m-1+8=0

We multiply all the terms by the denominator


-m*5m-1*5m+8*5m+2=0

Wy multiply elements

-5m^2-5m+40m+2=0

We add all the numbers together, and all the variables

-5m^2+35m+2=0

a = -5; b = 35; c = +2;
Δ = b2-4ac
Δ = 352-4·(-5)·2
Δ = 1265
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-\sqrt{1265}}{2*-5}=\frac{-35-\sqrt{1265}}{-10}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+\sqrt{1265}}{2*-5}=\frac{-35+\sqrt{1265}}{-10}
$