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2/5mm=X

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Solution for 2/5mm=X equation:



2/5mm=m
We move all terms to the left:
2/5mm-(m)=0
Domain of the equation: 5mm!=0
m!=0/1
m!=0
m∈R
We add all the numbers together, and all the variables
-1m+2/5mm=0
We multiply all the terms by the denominator
-1m*5mm+2=0
Wy multiply elements
-5m^2+2=0
a = -5; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-5)·2
Δ = 40
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
m_{1}=\frac{-b-\sqrt{\Delta}}{2a}
m_{2}=\frac{-b+\sqrt{\Delta}}{2a}

The end solution:
\sqrt{\Delta}=\sqrt{40}=\sqrt{4*10}=\sqrt{4}*\sqrt{10}=2\sqrt{10}
m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{10}}{2*-5}=\frac{0-2\sqrt{10}}{-10} =-\frac{2\sqrt{10}}{-10} =-\frac{\sqrt{10}}{-5}
m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{10}}{2*-5}=\frac{0+2\sqrt{10}}{-10} =\frac{2\sqrt{10}}{-10} =\frac{\sqrt{10}}{-5}

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