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2/5n-9=n
We move all terms to the left:
2/5n-9-(n)=0
Domain of the equation: 5n!=0We add all the numbers together, and all the variables
n!=0/5
n!=0
n∈R
-1n+2/5n-9=0
We multiply all the terms by the denominator
-1n*5n-9*5n+2=0
Wy multiply elements
-5n^2-45n+2=0
a = -5; b = -45; c = +2;
Δ = b2-4ac
Δ = -452-4·(-5)·2
Δ = 2065
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-\sqrt{2065}}{2*-5}=\frac{45-\sqrt{2065}}{-10} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+\sqrt{2065}}{2*-5}=\frac{45+\sqrt{2065}}{-10} $
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