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2/5p+4=3/10p+5
We move all terms to the left:
2/5p+4-(3/10p+5)=0
Domain of the equation: 5p!=0
p!=0/5
p!=0
p∈R
Domain of the equation: 10p+5)!=0We get rid of parentheses
p∈R
2/5p-3/10p-5+4=0
We calculate fractions
20p/50p^2+(-15p)/50p^2-5+4=0
We add all the numbers together, and all the variables
20p/50p^2+(-15p)/50p^2-1=0
We multiply all the terms by the denominator
20p+(-15p)-1*50p^2=0
Wy multiply elements
-50p^2+20p+(-15p)=0
We get rid of parentheses
-50p^2+20p-15p=0
We add all the numbers together, and all the variables
-50p^2+5p=0
a = -50; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-50)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-50}=\frac{-10}{-100} =1/10 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-50}=\frac{0}{-100} =0 $
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