2/5s-2+3s-33=50

Solution for 2/5s-2+3s-33=50 equation:

2/5s-2+3s-33=50

We move all terms to the left:

2/5s-2+3s-33-(50)=0


Domain of the equation: 5s!=0

s!=0/5

s!=0

s∈R


We add all the numbers together, and all the variables

3s+2/5s-85=0

We multiply all the terms by the denominator


3s*5s-85*5s+2=0

Wy multiply elements

15s^2-425s+2=0

a = 15; b = -425; c = +2;
Δ = b2-4ac
Δ = -4252-4·15·2
Δ = 180505
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-425)-\sqrt{180505}}{2*15}=\frac{425-\sqrt{180505}}{30}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-425)+\sqrt{180505}}{2*15}=\frac{425+\sqrt{180505}}{30}
$