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2/5v=10v=25
We move all terms to the left:
2/5v-(10v)=0
Domain of the equation: 5v!=0We add all the numbers together, and all the variables
v!=0/5
v!=0
v∈R
-10v+2/5v=0
We multiply all the terms by the denominator
-10v*5v+2=0
Wy multiply elements
-50v^2+2=0
a = -50; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-50)·2
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20}{2*-50}=\frac{-20}{-100} =1/5 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20}{2*-50}=\frac{20}{-100} =-1/5 $
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