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2/5x+1/10x=15
We move all terms to the left:
2/5x+1/10x-(15)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 10x!=0We calculate fractions
x!=0/10
x!=0
x∈R
20x/50x^2+5x/50x^2-15=0
We multiply all the terms by the denominator
20x+5x-15*50x^2=0
We add all the numbers together, and all the variables
25x-15*50x^2=0
Wy multiply elements
-750x^2+25x=0
a = -750; b = 25; c = 0;
Δ = b2-4ac
Δ = 252-4·(-750)·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-25}{2*-750}=\frac{-50}{-1500} =1/30 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+25}{2*-750}=\frac{0}{-1500} =0 $
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