2/5x+1/x=35

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Solution for 2/5x+1/x=35 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(2/5)*x+1/x = 35 // - 35

(2/5)*x+1/x-35 = 0

2/5*x^1+1*x^-1-35*x^0 = 0

(2/5*x^2-35*x^1+1*x^0)/(x^1) = 0 // * x^2

x^1*(2/5*x^2-35*x^1+1*x^0) = 0

x^1

(2/5)*x^2-35*x+1 = 0

(2/5)*x^2-35*x+1 = 0

DELTA = (-35)^2-(1*4*(2/5))

DELTA = 6117/5

DELTA > 0

x = ((6117/5)^(1/2)+35)/(2*(2/5)) or x = (35-(6117/5)^(1/2))/(2*(2/5))

x = 5/4*((6117/5)^(1/2)+35) or x = 5/4*(35-(6117/5)^(1/2))

x in { 5/4*(35-(6117/5)^(1/2)), 5/4*((6117/5)^(1/2)+35)}

x in { 5/4*(35-(6117/5)^(1/2)), 5/4*((6117/5)^(1/2)+35) }

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